2x^2+17x+41=5

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Solution for 2x^2+17x+41=5 equation:


Simplifying
2x2 + 17x + 41 = 5

Reorder the terms:
41 + 17x + 2x2 = 5

Solving
41 + 17x + 2x2 = 5

Solving for variable 'x'.

Reorder the terms:
41 + -5 + 17x + 2x2 = 5 + -5

Combine like terms: 41 + -5 = 36
36 + 17x + 2x2 = 5 + -5

Combine like terms: 5 + -5 = 0
36 + 17x + 2x2 = 0

Factor a trinomial.
(9 + 2x)(4 + x) = 0

Subproblem 1

Set the factor '(9 + 2x)' equal to zero and attempt to solve: Simplifying 9 + 2x = 0 Solving 9 + 2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + 2x = 0 + -9 Combine like terms: 9 + -9 = 0 0 + 2x = 0 + -9 2x = 0 + -9 Combine like terms: 0 + -9 = -9 2x = -9 Divide each side by '2'. x = -4.5 Simplifying x = -4.5

Subproblem 2

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Solution

x = {-4.5, -4}

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